Find the equation of the line with y-intercept -2 and passing though the point (2,5). Show your work. What is the equation of a line perpendicular to this line, but with the same y-intercept? (Have no idea how to do this can someone please explain)

equation of a line with y intercept of neg.2 is y=mx-2you could use pint slope[y-y1=m(x-x1)], but i preffer slope intercept form [y=mx+b]5=m2-2move 2 to the other side7=m2divide both sides by 23.5=mso, the slope is 3.5equation for a line that passes through point (2,5) with a y intercept of -2 is y=3.5x-2the equation of a perpendicular line to the line y=3.5x-2 has a slope that is negative reciprical of 3.5we keep the everything on y=3.5x-2 same except the slope.negative reciprical slope of 3.5 is -[tex] - \frac{10}{35} [/tex]simplify [tex] - \frac{2}{7} [/tex]so, the equation of a line perpendicular to the first one is y=-2/7x-2